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方法的声明:
public BigDecimal divide(BigDecimal divisor, int scale, int roundingMode)
参数解析:
divisor是除数,scale是精确度,roundingMode是结果的取值方式。
返回值:
返回的结果也是一个BigDecimal
测试案例:
同时解释一下roundingMode的五种模式
案例1
/**
* Rounding mode to round towards zero. Never increments the digit
* prior to a discarded fraction (i.e., truncates). Note that this
* rounding mode never increases the magnitude of the calculated value.
*/
public final static int ROUND_DOWN = 1;
案例2:
/**
* Rounding mode to round towards positive infinity. If the
* {@code BigDecimal} is positive, behaves as for
* {@code ROUND_UP}; if negative, behaves as for
* {@code ROUND_DOWN}. Note that this rounding mode never
* decreases the calculated value.
*/
public final static int ROUND_CEILING = 2;
案例3:
/**
* Rounding mode to round towards negative infinity. If the
* {@code BigDecimal} is positive, behave as for
* {@code ROUND_DOWN}; if negative, behave as for
* {@code ROUND_UP}. Note that this rounding mode never
* increases the calculated value.
*/
public final static int ROUND_FLOOR = 3;
案例4:
案例:
/**
* Rounding mode to round towards {@literal “nearest neighbor”}
* unless both neighbors are equidistant, in which case round
* down. Behaves as for {@code ROUND_UP} if the discarded
* fraction is {@literal >} 0.5; otherwise, behaves as for
* {@code ROUND_DOWN}.
*/
public final static int ROUND_HALF_DOWN = 5;
补充其他方法:
BigDecimal.setScale()方法用于格式化小数点
setScale(1)表示保留一位小数,默认用四舍五入方式
setScale(1,BigDecimal.ROUND_DOWN)直接删除多余的小数位,如2.35会变成2.3
setScale(1,BigDecimal.ROUND_UP)进位处理,2.35变成2.4
setScale(1,BigDecimal.ROUND_HALF_UP)四舍五入,2.35变成2.4
setScaler(1,BigDecimal.ROUND_HALF_DOWN)四舍五入,2.35变成2.3,如果是5则向下舍
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