用verilog实现特殊功能的触发器

用verilog实现特殊功能的触发器对输入上升沿捕获触发器moduletop_module(inputclk,input[7:0]in,output[7:0]pedge);reg[7:0]in1;always@(posedgeclk)beginin1<=in;pedge=in&~in1;endendmodule对时钟双边沿触发器不可以用always@(posedgeclkornegedgeclk

大家好,欢迎来到IT知识分享网。用verilog实现特殊功能的触发器"

对输入上升沿捕获触发器

module top_module (
    input clk,
    input [7:0] in,
    output [7:0] pedge
);
    reg [7:0] in1;
    always@(posedge clk)begin
        in1<=in;
        pedge=in&~in1;
    end
endmodule

对时钟双边沿触发器
不可以用always@(posedge clk or negedge clk),因为该语句在FPGA中不可综合。
应运用a^ 0=a,a^a=0;

module top_module(
	input clk,
	input d,
	output q);
	
	reg p, n;
	
	// A positive-edge triggered flip-flop
    always @(posedge clk)
        p <= d ^ n;
        
    // A negative-edge triggered flip-flop
    always @(negedge clk)
        n <= d ^ p;
    
    // Why does this work? 
    // After posedge clk, p changes to d^n. Thus q = (p^n) = (d^n^n) = d.
    // After negedge clk, n changes to p^n. Thus q = (p^n) = (p^p^n) = d.
    // At each (positive or negative) clock edge, p and n FFs alternately
    // load a value that will cancel out the other and cause the new value of d to remain.
    assign q = p ^ n;
    
    
	// Can't synthesize this.
	/*always @(posedge clk, negedge clk) begin
		q <= d;
	end*/
    
    
endmodule

详情见 HDLbits flip-flop.

免责声明:本站所有文章内容,图片,视频等均是来源于用户投稿和互联网及文摘转载整编而成,不代表本站观点,不承担相关法律责任。其著作权各归其原作者或其出版社所有。如发现本站有涉嫌抄袭侵权/违法违规的内容,侵犯到您的权益,请在线联系站长,一经查实,本站将立刻删除。 本文来自网络,若有侵权,请联系删除,如若转载,请注明出处:https://yundeesoft.com/15691.html

(0)

相关推荐

发表回复

您的邮箱地址不会被公开。 必填项已用 * 标注

关注微信